document.write( "Question 975291: log 27 base 3+log 64 base 4 \n" ); document.write( "
Algebra.Com's Answer #597068 by Edwin McCravy(20060)\"\" \"About 
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log 27 base 3+log 64 base 4 or
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document.write( "log327 + log364 \r\n" );
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document.write( "log 27 base 3\r\n" );
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document.write( "That means the exponent (power) to which you must raise 3 to get 27.\r\n" );
document.write( "Since we must raise 3 to the 3rd power to get 27, then: \r\n" );
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document.write( "log 27 base 3 which is written log327 = 3 because 33 = 27.  \r\n" );
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document.write( "So\r\n" );
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document.write( "log 64 base 4\r\n" );
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document.write( "That means the exponent (power) to which you must raise 4 to get 64.\r\n" );
document.write( "Since we must raise 4 to the 3rd power to get 64, then:  \r\n" );
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document.write( "log 64 base 3 which is written log364 = 3 because 43 = 64.\r\n" );
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document.write( "So answer = log327 + log364 = 3+3 = 6.\r\n" );
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document.write( "Edwin
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