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document.write( "I'll just do the first one. \r\n" );
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document.write( "Factor the numerator and denominator:\r\n" );
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document.write( "Setting the denominator = 0, 3x(x-3) = 0, tells us that\r\n" );
document.write( "we have discontinuities at x=0, and at x=3\r\n" );
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document.write( "We must decide which type of discontinuity we have at 0 and 3.\r\n" );
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document.write( "1. If we can cancel a common factor in the numerator and denominator\r\n" );
document.write( "and remove the discontinuity, then it is a \"removable discontinuity\" \r\n" );
document.write( "or \"a hole in the graph\".\r\n" );
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document.write( "2. If we can't cancel a factor, then the discontinuity is infinite and \r\n" );
document.write( "there is an asymptote there.\r\n" );
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document.write( "We have one of each type.\r\n" );
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document.write( "1. We can remove the discontinuity at x=0 by cancelling the x in the \r\n" );
document.write( "numerator and denominator. To find out where the hole is, we cancel\r\n" );
document.write( "the x and get a new function which is like the original function everywhere\r\n" );
document.write( "except at the hole. Let's call it g(x):\r\n" );
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document.write( "g(x) doesn't have a hole at x=0, we substitute and find \r\n" );
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document.write( "So f(x) has a hole at
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document.write( "2. We cannot remove the discontinuity at x=3 by cancelling, so there is\r\n" );
document.write( "a vertical asymptote there, a \"non-removable\" discontinuity.\r\n" );
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document.write( "Since the degree of the numerator and denominator have the same degree, 1,\r\n" );
document.write( "there is a horizontal asymptote at y = the ratio of the two leading\r\n" );
document.write( "coefficients, so the horizontal asymptote has equation y=1/3,\r\n" );
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document.write( "So we plot the hole at
, the vertical asymptote at x=3, and the horizontal \r\n" );
document.write( "asymptote at y=1/3:\r\n" );
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document.write( "Edwin
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