document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975271>Question 975271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the step by step solution for graphing y=x^2-6x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597048 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This one is factorable.  Find the zeros and the x coordinate of the vertex; and use this to evaluate y for this vertex.  Pick two or three more x values and find corresponding y values.  Just plot all these points and do you best sketching.\r<BR>\n" );
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document.write( "To start, <BR>\n" );
document.write( "y=x(x-6)  so the zeros will be 0 and 6.  <BR>\n" );
document.write( "The x coordinate for the vertex is at x=3, the exact middle of 0 and 6.<BR>\n" );
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