document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975235>Question 975235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let &#952; be an angle in quadrant II such that sin&#952;= 12/13\r<BR>\n" );
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document.write( "Find  the exact values of sec&#952; and tan </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597033 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let &#952; be an angle in quadrant II such that sin&#952;= 12/13 <BR>\n" );
document.write( "Find the exact values of sec&#952; and tan<BR>\n" );
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document.write( "By deinition sin = y/r<BR>\n" );
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document.write( "Since sin(t) = 12/13, y = 12 and r = 13<BR>\n" );
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document.write( "Note: x is negative in QII<BR>\n" );
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document.write( "x = -sqrt[13^2-12^2] = -5<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "sec(t) = r/x = -13/5<BR>\n" );
document.write( "tan(t) = y/x = -12/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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