document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975226>Question 975226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the following ellipse:      \r<BR>\n" );
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document.write( "          (x + 2)2 + (y + 2)2 = 1                           <BR>\n" );
document.write( "               4             25\r<BR>\n" );
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document.write( "Find: a)Center :___________\r<BR>\n" );
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document.write( "         b)Vertices:___________<BR>\n" );
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document.write( "                           ___________\r<BR>\n" );
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document.write( "         c)  Foci:     ___________\r<BR>\n" );
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document.write( "                           ___________\r<BR>\n" );
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document.write( "        d) length of <BR>\n" );
document.write( "            major axis:________\r<BR>\n" );
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document.write( "        e) length of <BR>\n" );
document.write( "            minor axis:________\r<BR>\n" );
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document.write( "        f) eccentricity:________      <BR>\n" );
document.write( "                                                                      <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597022 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Center is (-2,-2)  You change the sign of each.<BR>\n" );
document.write( "The vertices are along the y-axis, since that is how the ellipse is oriented with regard to the major axis.  They are sqrt (25) or 5.  They are at (-2,-7) and (-2,+3)<BR>\n" );
document.write( "The major axis is 10 units long; the minor axis is 4 units long.  It is the square root of the denominator multiplied by 2.\r<BR>\n" );
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document.write( "a^2-c^2=b^2<BR>\n" );
document.write( "25-21=4<BR>\n" );
document.write( "c^2=21;; c= sqrt(21) ;  The foci are sqrt(21) from the center, along the y-axis, so they are at (-2, -2+sqrt(21) and (-2, -2- sqrt(21))\r<BR>\n" );
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document.write( "eccentricity is c/a, and that is sqrt (21)/5 </SPAN>\n" );
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