document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975217>Question 975217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of an ellipse, in standard form,  with center at (-1,3), vertex at (3,3) and minor axis of length 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #597020 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=597020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The vertex is 4 units from the center and the minor axis is 2 units long, so the semi-minor axis is 1 unit.\r<BR>\n" );
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document.write( "a^2 will be 16 and b^2=1\r<BR>\n" );
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document.write( "{(x+1)^2/16} + {(b-3)^2)/1}=1\r<BR>\n" );
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document.write( "a^2-c^2=b^2<BR>\n" );
document.write( "16-c^2=1<BR>\n" );
document.write( "c^2=15<BR>\n" );
document.write( "c= +/- sqrt (15).  Those are foci.\r<BR>\n" );
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document.write( "{(x+1)^2/16} + {(b-3)^2)/1}=1\r<BR>\n" );
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