document.write( "Question 11543: when you give me the answer could you explain it please so that i understand.\r
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document.write( "It takes 1 hour longer to fly to St. Paul at 200mi/h than it does to return at 250 mi/h. How far away is St. Paul? \n" );
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Algebra.Com's Answer #5970 by vasu2qute(17)![]() ![]() ![]() You can put this solution on YOUR website! let us assume that it takes xhrs to return at 250mi/hr \n" ); document.write( "then time taken to fly to St.Paul = (x+1)hrs at 200m/hr \n" ); document.write( "distance=time x speed \n" ); document.write( "onward distance= 250x \n" ); document.write( "return distance=200(x+1) \n" ); document.write( "onward distance=return distance \n" ); document.write( "250x=200(x+1) \n" ); document.write( "250x=200x+200 \n" ); document.write( "250-200x=200 \n" ); document.write( "50x=200 \n" ); document.write( "x=200/50 \n" ); document.write( "x=4hrs \n" ); document.write( "distance=250x=250x4=1000miles \n" ); document.write( " |