document.write( "Question 11543: when you give me the answer could you explain it please so that i understand.\r
\n" ); document.write( "\n" ); document.write( "It takes 1 hour longer to fly to St. Paul at 200mi/h than it does to return at 250 mi/h. How far away is St. Paul?
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Algebra.Com's Answer #5970 by vasu2qute(17)\"\" \"About 
You can put this solution on YOUR website!
let us assume that it takes xhrs to return at 250mi/hr
\n" ); document.write( "then time taken to fly to St.Paul = (x+1)hrs at 200m/hr
\n" ); document.write( "distance=time x speed
\n" ); document.write( "onward distance= 250x
\n" ); document.write( "return distance=200(x+1)
\n" ); document.write( "onward distance=return distance
\n" ); document.write( "250x=200(x+1)
\n" ); document.write( "250x=200x+200
\n" ); document.write( "250-200x=200
\n" ); document.write( "50x=200
\n" ); document.write( "x=200/50
\n" ); document.write( "x=4hrs
\n" ); document.write( "distance=250x=250x4=1000miles
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