document.write( "Question 975188: Suppose f(x) =x^2 over the domain of f, then f^-1(x)=?
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Algebra.Com's Answer #596999 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "if $\"f%28x%29=x%5E2\"$ , then inverse $\"f%5E%28-1%29%28x%29\"$ will be:\r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=x%5E2\"$ .......recall that $\"f%28x%29=y\"$ , so we have\r
\n" ); document.write( "\n" ); document.write( " $\"y=x%5E2\"$ ...........swap $\"x\"$ and $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=y%5E2\"$ .......solve for $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=+sqrt%28x%29\"$ , your inverse $\"f%5E%28-1%29%28x%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%5E%28-1%29%28x%29+=+sqrt%28x%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "so, your answer is: (A) $\"f%5E%28-1%29%28x%29+=+sqrt%28x%29\"$ \n" ); document.write( "

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