document.write( "Question 82988This question is from textbook introductory algebra
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document.write( ": a plane flying with the jet stream flew from los angeles to chicago, a distance of 2250 mi, in 5 h. flying aganst the jet stream, the plane couldfly only 1750 mi in the same amount of time. find the rate of the plane in calm air and the rate of wind. \n" );
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Algebra.Com's Answer #59698 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a plane flying with the jet stream flew from los angeles to chicago, a distance of 2250 mi, in 5 h. flying against the jet stream, the plane could fly only 1750 mi in the same amount of time. find the rate of the plane in calm air and the rate of wind. \n" ); document.write( ": \n" ); document.write( "Let x = speed of plane in still air \n" ); document.write( "Let y = speed of the jet stream \n" ); document.write( "Then: \n" ); document.write( "(x+y) = speed with the jetstream \n" ); document.write( "(x-y) = speed against the jetstream \n" ); document.write( ": \n" ); document.write( "Write two distance equations: Distance = time * speed \n" ); document.write( "5(x + y) = 2250 \n" ); document.write( "5(x - y) = 1750 \n" ); document.write( ": \n" ); document.write( "Simplify both equations, divide by 5 \n" ); document.write( "x + y = 450 \n" ); document.write( "x - y = 350 \n" ); document.write( "------------- adding eliminates y \n" ); document.write( "2x + 0 = 800 \n" ); document.write( "x = 800/2 \n" ); document.write( "x = 400 mph in still air \n" ); document.write( ": \n" ); document.write( "Find y using x + y = 800 \n" ); document.write( "400 + y = 450 \n" ); document.write( "y = 50 mph speed of the jet stream \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions by finding the distance at both speeds: \n" ); document.write( "5*450 = 2250 \n" ); document.write( "5*350 = 1750 \n" ); document.write( ": \n" ); document.write( "Make sense to you? Any questions? \n" ); document.write( " |