document.write( "Question 83164: This one is tough for me, any help is appreciated:\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " $\"%28x%5E7y%5E4z%5E0%29%2F%285%5E-2x%5E3y%5E-8z%5E-9%29%5E2\"$ \n" ); document.write( "

Algebra.Com's Answer #59693 by Mona27(45) $\"\"$ $\"About$

You can put this solution on YOUR website!
First try expanding the bottom bracket (if I understand correctly the last number you put down was a power of 2)
\n" ); document.write( "This means that each power in the bottom expression will be multiplied by 2:
\n" ); document.write( " $\"%28x%5E7y%5E4z%5E0%29%2F%285%5E-4x%5E6y%5E-16z%5E-18%29\"$
\n" ); document.write( "Next deal with the numbers:
\n" ); document.write( " $\"1%2F5%5E-4=5%5E4=625\"$
\n" ); document.write( "Then terms in x:
\n" ); document.write( " $\"x%5E7%2Fx%5E6=x\"$
\n" ); document.write( "Then terms in y:
\n" ); document.write( " $\"y%5E4%2Fy%5E-16=y%5E20\"$
\n" ); document.write( "And finally z:
\n" ); document.write( " $\"z%5E0%2Fz%5E-18=z%5E18\"$
\n" ); document.write( "So it all becomes
\n" ); document.write( " $\"625xy%5E20z%5E18\"$ \n" ); document.write( "

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