document.write( "Question 975102: (5x^0y^-7/2x^-2y^4)^-2 \n" ); document.write( "
Algebra.Com's Answer #596915 by Boreal(15235) You can put this solution on YOUR website! (5x^0y^-7/2x^-2y^4)^-2;;; 5x^0=1 ;;;y^(-7/2)*(-2)=y^7;;;; (-2)^-2=(1/(-2)^2) or (1/4);;;(y^4)^-2=y^-8\r \n" ); document.write( "\n" ); document.write( "1* y^7*(1/4)y^-8 \n" ); document.write( "y^7/(1/4)y^8\r \n" ); document.write( "\n" ); document.write( "(4/y) \n" ); document.write( " |