document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975032>Question 975032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Bus is travelling with 52 passengers. When it arrives at a stop y passengers get off and 4 get on. At the next stop one third of the passengers get off and 3 get on. There are now 25 passengers. Find y. Please help!! thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596914 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 52=number\r<BR>\n" );
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document.write( "52-y+4\r<BR>\n" );
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document.write( "(2/3) (52-y+4)+3=25   ;; (1/3) get off, so (2/3) left\r<BR>\n" );
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document.write( "(2/3)(52-y+4) =22\r<BR>\n" );
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document.write( "52-y+4=33<BR>\n" );
document.write( "-y=-23<BR>\n" );
document.write( "y=23\r<BR>\n" );
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document.write( "52 started<BR>\n" );
document.write( "23 got off<BR>\n" );
document.write( "29 left<BR>\n" );
document.write( "4 got on<BR>\n" );
document.write( "33<BR>\n" );
document.write( "11 get off next stop<BR>\n" );
document.write( "22<BR>\n" );
document.write( "3 get on <BR>\n" );
document.write( "25\r<BR>\n" );
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document.write( "y is 23\r<BR>\n" );
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document.write( "Important when (1/3) get off that (2/3) remain. </SPAN>\n" );
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