document.write( "Question 975100: If the perimeter of a rectangle is 24 and the length is two times it's width find the width of the rectangle and the area of the rectangle.
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Algebra.Com's Answer #596910 by lwsshak3(11628) $\"\"$ $\"About$

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If the perimeter of a rectangle is 24 and the length is two times it's width find the width of the rectangle and the area of the rectangle.
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\n" ); document.write( "let x=width of rectangle
\n" ); document.write( "2x=length of rectangle
\n" ); document.write( "2(width+length)=perimeter
\n" ); document.write( "2(x+2x)=24
\n" ); document.write( "6x=24
\n" ); document.write( "x=4
\n" ); document.write( "2x=8
\n" ); document.write( "length*width=area
\n" ); document.write( "8*4=32
\n" ); document.write( "width=4
\n" ); document.write( "length=8
\n" ); document.write( "area=32 sq units \n" ); document.write( "

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