document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975049>Question 975049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if Log2=.3010 and log3=.4771, then find <BR>\n" );
document.write( "     (A) log1/25	(b) log3.002    <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596854 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if Log2=.3010 and log3=.4771, then find <BR>\n" );
document.write( "     (A) log1/25	<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "1/25 = log(0.04) = log(2^2/100)<BR>\n" );
document.write( "= 2log(2) - log(100)<BR>\n" );
document.write( "= 0.602 - 2<BR>\n" );
document.write( "= -1.398<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "(b) log3.002<BR>\n" );
document.write( "3.002 can't be expressed as a product of 2, 3 & 10<BR>\n" );
document.write( "  </SPAN>\n" );
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