document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968929>Question 968929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 20 percent acid solution to obtain 48 L of a 40 percent acid solution. What amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596852 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 20 percent acid solution to obtain 48 L of a 40 percent acid solution. What amounts of each should be used?<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "T = amount of 20%<BR>\n" );
document.write( "P = amount of pure (100%)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "T + P = 48  (total liquid)<BR>\n" );
document.write( "20T + 100P = 48*40 (total acid)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "20T + 100P = 1920<BR>\n" );
document.write( "T + 5P = 96<BR>\n" );
document.write( "T + P = 48<BR>\n" );
document.write( "---------------------- Subtract<BR>\n" );
document.write( "4P = 48<BR>\n" );
document.write( "etc </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );