document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=968929>Question 968929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 20 percent acid solution to obtain 48 L of a 40 percent acid solution. What amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596843 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solvable with a single variable.\r<BR>\n" );
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document.write( "Let v be volume of the pure acid  (ASSUMING it is a liquid), and then 48-v is the volume of the 20% solution liquid.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28100v%2B20%2848-v%29%29%2F48=40 ALIGN=MIDDLE  ALT=\"%28100v%2B20%2848-v%29%29%2F48=40\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is accounting for percents.  Numerator is amount of solute, and denominator is amount of solution result. </SPAN>\n" );
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