document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=969103>Question 969103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ms. Folgers has some coffee that sells for $4 per pound and a second coffee that sells for $8 per pound. She<BR>\n" );
document.write( "wants to mix the two coffees to make 50 pounds of coffee that will sell for $5.60 per pound. How many<BR>\n" );
document.write( "pounds of each coffee should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596842 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This can be solved using a single variable.\r<BR>\n" );
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document.write( "Let x be the amount of the $4 per pound coffee and then 50-x will be the amount of the $8 per pound coffee.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284x%2B8%2850-x%29%29%2F50=5.60 ALIGN=MIDDLE  ALT=\"%284x%2B8%2850-x%29%29%2F50=5.60\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve the equation for x, and use the found value to compute 50-x. </SPAN>\n" );
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