document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=975001>Question 975001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a degree 3 polynomial that has zeros -2, 3 and 6 and in which the coefficient of x^2 is -14?\r<BR>\n" );
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document.write( "ok.. I know the zeros would be (x+2) (x-3) (x-6).. then I get lost with the -14x^2..<BR>\n" );
document.write( "can someone please help find what the polynomial is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596824 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39632)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What?  Just finish!  The binomial product makes the zeros work.  That product by itself has leading coefficient of 1.  Just apply the factor, -14. </SPAN>\n" );
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