document.write( "Question 83167: Which of the folowing are the pair of equations whose graphs are not perpendicular?\r
\n" ); document.write( "\n" ); document.write( "A. 2x-8y=9
\n" ); document.write( " 12x-3y=7\r
\n" ); document.write( "\n" ); document.write( "B.3x+6y=8
\n" ); document.write( " y=2x-8\r
\n" ); document.write( "\n" ); document.write( "C.y=x-7
\n" ); document.write( " x+y=3\r
\n" ); document.write( "\n" ); document.write( "D. 2y=3x+5
\n" ); document.write( " 2x+3y=4
\n" ); document.write( "

Algebra.Com's Answer #59681 by Mona27(45)\"\" \"About 
You can put this solution on YOUR website!
It's the first one (A)
\n" ); document.write( "That's because the product of the gradients (slopes) of two perpendicular lines must be -1.\r
\n" ); document.write( "\n" ); document.write( "In the first case:
\n" ); document.write( "the gradient of the first line = \"2%2F8=1%2F4\"
\n" ); document.write( "and the gradient of the second line = \"12%2F3=4\"\r
\n" ); document.write( "\n" ); document.write( "since both gradients are positive then they cannot give a product of -1, and therefore are not perpendicular.
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