document.write( "Question 974957: The polynomial of degree 3 , P(x) , has a root of multiplicity 2 at x=4 and a root of multiplicity 1 at x=-4 . The y-intercept is y=-12.8 .
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document.write( " Find a formula for P(x) \r
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document.write( "what I have tried.. -12.8=a(x-4)^2(x+4)
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document.write( "I get confused and start adding steps I shouldn't. \n" );
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Algebra.Com's Answer #596769 by Edwin McCravy(20065) You can put this solution on YOUR website! The polynomial of degree 3 , P(x) , has a root of multiplicity 2 at x=4 and a root of multiplicity 1 at x=-4 . The y -intercept is y=-12.8 . \n" ); document.write( "Find a formula for P(x) \n" ); document.write( "what I have tried.. -12.8=a(x-4)^2(x+4) \n" ); document.write( "I get confused and start adding steps I shouldn't. \n" ); document.write( "----------- \n" ); document.write( " \r\n" ); document.write( "You were on the right track with\r\n" ); document.write( "\r\n" ); document.write( " a(x-4)^2(x+4), \r\n" ); document.write( "\r\n" ); document.write( "but leave P(x) equal to that:\r\n" ); document.write( "\r\n" ); document.write( "P(x) = a(x-4)^2(x+4) \r\n" ); document.write( "\r\n" ); document.write( "Now use this given fact:\r\n" ); document.write( " \n" ); document.write( "The y -intercept is y=−12.8 \n" ); document.write( " \r\n" ); document.write( "Think about what y-intercept means. Remember that y = P(x). The y-intercept\r\n" ); document.write( "being -12.8 means that when you substitute x=0, you get y = P(0) = -12.8\r\n" ); document.write( "\r\n" ); document.write( "So substitute x=0 in\r\n" ); document.write( "\r\n" ); document.write( "P(x) = a(x-4)^2(x+4) \r\n" ); document.write( "P(0) = a(0-4)^2(0+4)\r\n" ); document.write( "12.8 = a(-4)^2(4)\r\n" ); document.write( "12.8 = a(16)(4)\r\n" ); document.write( "12.8 = a(64)\r\n" ); document.write( "\n" ); document.write( " |