document.write( "Question 974950: Kaitlin swam 8 kilometers against the current in the same amount of time it took her to swim 16 kilometers with the current. The rate of the current was 1
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Algebra.Com's Answer #596749 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
speed = x kph\r
\n" ); document.write( "\n" ); document.write( "(x-1)*t=8; 8/(x-1)= t units are km
\n" ); document.write( "(x+1)t=16; 16/(x+1)=t\r
\n" ); document.write( "\n" ); document.write( "Set them equal to each other\r
\n" ); document.write( "\n" ); document.write( "8/(x-1)=16/(x+1)
\n" ); document.write( "cross multiply\r
\n" ); document.write( "\n" ); document.write( "8x+8=16x-16
\n" ); document.write( "-8x=-24
\n" ); document.write( "x=3 kph\r
\n" ); document.write( "\n" ); document.write( "2kph against; 4kph with
\n" ); document.write( "Took her 4 hours to go 8 kph against
\n" ); document.write( "Took her 4 hours to go 16 kph with
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