document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974915>Question 974915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me factorize this expression :<BR>\n" );
document.write( "x^3 - 23x^2 + 142x - 120 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596726 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Several possible roots to check:  PLUS and MINUS of 1,2,3,4,5,10,12,20,30,40,60\r<BR>\n" );
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document.write( "Trying the first several minus values using synthetic division did not give nonzero remainders; but checking 1 as possible root, the PLUS, gave a remainder 0, and quotient coefficients 1,-22,120.\r<BR>\n" );
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document.write( "Now just use quadratic formula solution for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-22x%2B120=0 ALIGN=MIDDLE  ALT=\"x%5E2-22x%2B120=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >  to find two more roots or zeros.  Doing so gives roots x=10 and x=12.  This step not shown here because using the formula is uncomplicated to do.\r<BR>\n" );
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document.write( "The binomial factors for the expression used for writing the product is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%28x-1%29%28x-10%29%28x-12%29%29 ALIGN=MIDDLE  ALT=\"highlight%28%28x-1%29%28x-10%29%28x-12%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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