document.write( "Question 83157: 
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document.write( "The main road in Belleville is 7 3/10 miles long.\r\n" );
document.write( "so far 2 3/4 miles have been repaved. How many miles \r\n" );
document.write( "have not been repaved?
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Algebra.Com's Answer #59672 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The main road in Belleville is 7 3/10 miles long.\r\n" );
document.write( "so far 2 3/4 miles have been repaved. How many miles \r\n" );
document.write( "have not been repaved?\r\n" );
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document.write( " 7\"3%2F10\" =   7\"6%2F20\"  =  6\"26%2F20\"\r\n" );
document.write( "-2 \"3%2F4\" =  -2\"15%2F20\"  = -2\"15%2F20\"\r\n" );
document.write( "覧覧覧覧覧覧覧覧覧覧覧予r\n" );
document.write( "                  4\"11%2F20\"\r\n" );
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document.write( "The first step was to get the least common denominator\r\n" );
document.write( "of 10 and 4.  Since 20 is the smallest positive integer\r\n" );
document.write( "that both 10 and 4 will divide into evenly, 20 is the\r\n" );
document.write( "LCD. So we changed the \"3%2F10\" to \"6%2F20\" and changed the\r\n" );
document.write( "\"3%2F4\" to \"15%2F20\".  Then we noticed that the upper\r\n" );
document.write( "fraction \"6%2F20\" was smaller than the lower fraction\r\n" );
document.write( "\"15%2F20\", so to make the upper fraction larger, we \r\n" );
document.write( "borrowed 1 from the 7 leaving it as 6, then took the 1 that \r\n" );
document.write( "we borrowed, thought of it mentally as \"20%2F20\" \r\n" );
document.write( "and added it to the \"6%2F20\" making it \"26%2F20\".  Then \r\n" );
document.write( "we merely subtracted the whole parts and the fraction parts.\r\n" );
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document.write( "Edwin
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