document.write( "Question 974769: There is a sequence of numbers a1, a2, ... where a1 = 2, a2 = 3, and an = (an-1)/(an-2) for n> 3. What is the value of a1485? \n" ); document.write( "
Algebra.Com's Answer #596645 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I presume you mean\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you work out the first 12 terms, you will notice a pattern:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yes, indeed, the set of values repeats every six terms. Using integer division, divide 1485 by 6 and note the remainder. Count the number of terms in the list up to the remainder you just obtained, and that will be the value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |