document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=826151>Question 826151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the perpendicular distance formula to determine how many times the line, 3x-5y+16=0 intersects the circle x^2+y^2=5.\r<BR>\n" );
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document.write( "Thanks!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596599 by </B><A HREF=/tutors/aboutme.mpl?userid=Jamie-L><B>Jamie-L(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jamie-L><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So basically you are trying to find the perpendicular distance (which is the same as the shortest distance) 3x-5y+16=0 is closest to the circle (or (0,0), since the centre of the circle is (0,0))<BR>\n" );
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document.write( "By subbing the point (0,0) into the Perpendicular Distance Formula, you get:<BR>\n" );
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document.write( " abs(3(0)-5(0)+16) / sqrt(3^2+5^2)<BR>\n" );
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document.write( "which equals to 16/sqrt(34)<BR>\n" );
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document.write( "The radius of the circle is root 5. <BR>\n" );
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document.write( "16/sqrt(34) IS BIGGER than root 5. The line is further than the radius from the centre of the circle and therefore does not and cannot intersect the circle at any point. </SPAN>\n" );
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