document.write( "Question 83131: Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each day? \n" ); document.write( "
Algebra.Com's Answer #59656 by ankor@dixie-net.com(22740)\"\" \"About 
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Ariana took 2h longer to drive 360 mi on the first day of a trio than she took to drive 270 mi on the second day. If her speed was the same on both days what was the driving time each.
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\n" ); document.write( "Let t = time to drive 270 mi
\n" ); document.write( "Then (t+2) = time to drive 360 mi
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\n" ); document.write( "Since she drove the same speed on both legs of the trip, write a speed equation:
\n" ); document.write( "Speed = Distance/Time
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\n" ); document.write( "270 mi speed = 360 mi speed
\n" ); document.write( "\"270%2Ft\" = \"360%2F%28%28t%2B2%29%29\"
\n" ); document.write( "Cross multiply and you have:
\n" ); document.write( "360t = 270(t+2)
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\n" ); document.write( "360t = 270t + 540
\n" ); document.write( "360t - 270t = 540
\n" ); document.write( "90t = 540
\n" ); document.write( "t = 540/90
\n" ); document.write( "t = 6 hr to drive 270 mi, obviously it's 8 hrs to drive 360
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\n" ); document.write( "Check solution by confirming equal speeds:
\n" ); document.write( "270/6 = 45
\n" ); document.write( "360/8 = 45
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\n" ); document.write( "Make sense to you? Any questions?
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