document.write( "Question 83141This question is from textbook introductory algebra
\n" ); document.write( ": a pastry chef created a 50- ounce suger solution that wae 34% sugar from a 20% sugar solution and a 40% sugar solution. how much of the 20% sugar solution and how much of the 40% sugar solution were used? \n" ); document.write( "

Algebra.Com's Answer #59655 by josmiceli(19441) $\"\"$ $\"About$

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x = amount of 40% sugar solution needed
\n" ); document.write( "y = amount of 20% sugar solution needed
\n" ); document.write( " $\".4x+%2B+.2y+=+.34%2A50\"$
\n" ); document.write( "This can be read as \"Amount of sugar in 40% solution plus
\n" ); document.write( "amount of sugar in 20% solution equals the sugar in the 34% solution\"
\n" ); document.write( " $\".4x+%2B+.2y+=+17\"$
\n" ); document.write( "also
\n" ); document.write( " $\"x+%2B+y+=+50\"$
\n" ); document.write( "multiply both sides of 1st equation by .4
\n" ); document.write( " $\".4x+%2B+.4y+=+20\"$
\n" ); document.write( "multiply both sides by -1
\n" ); document.write( " $\"-.4x+-+.2y+=+-17\"$
\n" ); document.write( " $\"+.4x+%2B+.4y+=+20\"$ add these together
\n" ); document.write( " $\".2y+=+3\"$
\n" ); document.write( " $\"y+=+15\"$
\n" ); document.write( " $\"x+%2B+15+=+50\"$
\n" ); document.write( " $\"X+=+35\"$
\n" ); document.write( "So, there must be 35 ounces of the 40% solution and 15 ounces of the
\n" ); document.write( "20% solution to make 50 ounces of the 34% solution \n" ); document.write( "

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