document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974698>Question 974698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A BALL THROWN UPWARD WITH AN INITIAL VELOCITY OF 48 FT/SEC FROM A HEIGHT 864 FT.  ITS HEIGHT S, IN FEET, AFTER T SECONDS IS GIVEN BY S= -16T^2 +48T+864.  AFTER HOW LONG WILL THE BALL REACH THE GROUND? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596538 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A BALL THROWN UPWARD WITH AN INITIAL VELOCITY OF 48 FT/SEC FROM A HEIGHT 864 FT.  ITS HEIGHT S, IN FEET, AFTER T SECONDS IS GIVEN BY S= -16T^2 +48T+864.  AFTER HOW LONG WILL THE BALL REACH THE GROUND?<BR>\n" );
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document.write( "S= -16T^2 +48T+864 = 0<BR>\n" );
document.write( "S = 0 at impact<BR>\n" );
document.write( "Solve for t<BR>\n" );
document.write( "Ignore the negative solution.<BR>\n" );
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