document.write( "Question 974686: The graph of the equation x^2 + y^2 + 8x − 10y − 40 = 0 is which of the following conic sections?\r
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document.write( "A. parabola\r
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document.write( "B. hyperbola\r
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document.write( "C. ellipse\r
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document.write( "D. circle \n" );
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Algebra.Com's Answer #596534 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! If we rearrange the equation, grouping the x and y terms, and move the constant term to the other side, we have: \n" ); document.write( "x^2 + 8x + y^2 - 10y = 40 \n" ); document.write( "Complete the squares: \n" ); document.write( "(1) (x+4)^2 = x^2 + 8x + 16 \n" ); document.write( "(2) (y-5)^2 = y^2 - 10y + 25 \n" ); document.write( "Since the constant terms add to 41, we need to subtract this from the LHS in order to write the equation as the sum of (1) and (2): \n" ); document.write( "x^2 + 8x + y^2 - 10y -> (x+4)^2 + (y-5)^2 - 41 = 40 -> (x+4)^2 + (y-5)^2 = 81 \n" ); document.write( "This is the equation for a circle with center (-4,5), and radius sqrt(81) = 9 \n" ); document.write( "Graph is shown below. \n" ); document.write( "Ans: D circle \n" ); document.write( " ![]() |