document.write( "Question 974672: A coin is tossed 9 times and 3 heads appear. Can you conclude that the coin is not balanced? Use α = 0.10. Hint: Use the binomial table and find 2P (X ≤ 3) with p = 0.5 and n= 9. \r
\n" ); document.write( "\n" ); document.write( "The answer shown is \"No since p = 0.0508\". However, I still don't understand how this answer is given because when I refer to binomial table (using n=9, p= 0.5 and X= 3), I got p = 0.164. \r
\n" ); document.write( "\n" ); document.write( "Can someone show me the step by step working solution? Truly appreciate that. \n" ); document.write( "
Algebra.Com's Answer #596529 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
First, I think about the problem and see what makes sense. With a 50% probability, the expected value is 4.5, and 3 would not be unusual.
\n" ); document.write( "alpha = 0.10, probability of rejecting Ho given that it is true.\r
\n" ); document.write( "\n" ); document.write( "P (0) given p=0.5 is 0.001953
\n" ); document.write( "P(1) is 0.0176
\n" ); document.write( "P(2) is 0.0703
\n" ); document.write( "P(3) is 0.1641\r
\n" ); document.write( "\n" ); document.write( "I get a probability of 0.2539, which makes me fail to reject the null hypothesis and makes sense to me.\r
\n" ); document.write( "\n" ); document.write( "The only way I see \"508\" is if the decimal place was mistaken and p=0.508. That would be doubling the p-value obtained. If I am doing a 2-tail test, then I would double the p-value. Otherwise, I would accept the p-value I obtained. My guess is that the p-value was doubled, and the decimal point was misplaced.\r
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