document.write( "Question 974656: If PPQ (3 digit number) * Q = RQ5Q. Then what are P, Q, R \n" ); document.write( "
Algebra.Com's Answer #596516 by Edwin McCravy(20056)\"\" \"About 
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document.write( "Multiplication of a 3-digit number by a single digit can be \r\n" );
document.write( "performed like these two examples below:\r\n" );
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document.write( "  943                    458\r\n" );
document.write( "    7                      9\r\n" );
document.write( "   21 <--7x3              72  <--9x8\r\n" );
document.write( "  28  <--7x4             45   <--9x5\r\n" );
document.write( " 63   <--7x9            36    <--9x4\r\n" );
document.write( " 6601                   4122\r\n" );
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document.write( "So let QxQ=AB and QxP=CD\r\n" );
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document.write( "  PPQ\r\n" );
document.write( "    Q \r\n" );
document.write( "   AB <--QxQ\r\n" );
document.write( "  CD  <--QxP\r\n" );
document.write( " CD   <--QxP\r\n" );
document.write( " RQ5Q\r\n" );
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document.write( "B must = Q, since we bring it down to the bottom line\r\n" );
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document.write( "  PPQ\r\n" );
document.write( "    Q \r\n" );
document.write( "   AQ <--QxQ\r\n" );
document.write( "  CD  <--QxP\r\n" );
document.write( " CD   <--QxP\r\n" );
document.write( " RQ5Q \r\n" );
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document.write( "We need Q so that QxQ ends in Q\r\n" );
document.write( "1x1=1, 2x2=4, 3x3=9, 4x4=16, 5x5=25, 6x6=36, 7x7=49, 8x8=64, 9x9=81\r\n" );
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document.write( "Since QxQ must end in Q, Q is 6, since Q obviously can't be 1.\r\n" );
document.write( "Therefore AQ must be 36.\r\n" );
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document.write( "  PP6\r\n" );
document.write( "    6 \r\n" );
document.write( "   36 <--6x6\r\n" );
document.write( "  CD  <--6xP\r\n" );
document.write( " CD   <--6xP\r\n" );
document.write( " R656\r\n" );
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document.write( "In order to get the 5 on the bottom line, D must be 2.\r\n" );
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document.write( "  PP6\r\n" );
document.write( "    6 \r\n" );
document.write( "   36 <--6x6\r\n" );
document.write( "  C2  <--6xP\r\n" );
document.write( " C2   <--6xP\r\n" );
document.write( " R656\r\n" );
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document.write( "In order to get the left-most 6 on the bottom line, C must be 4,\r\n" );
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document.write( "  PP6\r\n" );
document.write( "    6 \r\n" );
document.write( "   36 <--6x6\r\n" );
document.write( "  42  <--6xP\r\n" );
document.write( " 42   <--6xP\r\n" );
document.write( " R656\r\n" );
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document.write( "and then P must be 7, since 6x7=42\r\n" );
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document.write( "  776\r\n" );
document.write( "    6 \r\n" );
document.write( "   36 <--6x6\r\n" );
document.write( "  42  <--6x7\r\n" );
document.write( " 42   <--6x7\r\n" );
document.write( " R656\r\n" );
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document.write( "Finally R can only be 4\r\n" );
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document.write( "  776\r\n" );
document.write( "    6 \r\n" );
document.write( "   36 <--6x6\r\n" );
document.write( "  42  <--6x7\r\n" );
document.write( " 42   <--6x7\r\n" );
document.write( " 4656\r\n" );
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document.write( "Edwin
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