document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974670>Question 974670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> skecth the graph y =3-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596514 by </B><A HREF=/tutors/aboutme.mpl?userid=anand429><B>anand429(138)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anand429><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=anand429><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 3-2x<BR>\n" );
document.write( "For x = -1, 0 and 1<BR>\n" );
document.write( "y = 5,3,1 respectively<BR>\n" );
document.write( "So plotting (-1,5),(0,3) and (1,1) and joining them in a straight line, we get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C-5%2C5%2C-7%2C13%2C3-2x%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C-5%2C5%2C-7%2C13%2C3-2x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );