document.write( "Question 974490: What is the vertex, focus, and directrix of x=1/2y^2+3 \n" ); document.write( "

Algebra.Com's Answer #596467 by lwsshak3(11628) $\"\"$ $\"About$

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What is the vertex, focus, and directrix of
\n" ); document.write( "x=1/2y^2+3
\n" ); document.write( "2x=y^2+6
\n" ); document.write( "y^2=2x-6
\n" ); document.write( "y^2=2(x-3)
\n" ); document.write( "This is an equation of a parabola that opens rightward,
\n" ); document.write( "Its basic form: (y-k)^2=4p(x-h), (h,k)=coordinates of the vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (3,0)
\n" ); document.write( "axis of symmetry: y=0
\n" ); document.write( "4p=2
\n" ); document.write( "p=2/4=1/2
\n" ); document.write( "focus: (3.5,0) (p-distance right of vertex on the axis of symmetry)
\n" ); document.write( "directrix: x= 2.5 (p-distance left of vertex on the axis of symmetry)
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