document.write( "Question 974575: 4cosx+5cosx=4
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\n" ); document.write( "The answer is: cosx=(4/9), right?\r
\n" ); document.write( "\n" ); document.write( "But, how do you write this in terms of arccos θ? Would it be: arcoss(4/9)+2πk, for any integer k, or +/-arcoss(4/9)+2π k, for any integer k, or is there just not a solution?
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Algebra.Com's Answer #596442 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"4cos%28x%29%2B5cos%28x%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"9cos%28x%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28x%29=4%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "x is the arc value.
\n" ); document.write( "\"4%2F9\" is the cosine.
\n" ); document.write( "x would terminate in quadrant 1 or quadrant 4, because its cosine is positive. You would need a period of \"2pi\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=arcos%284%2F9%29%2B2k%2Api\", for any integer k.
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