document.write( "Question 974575: 4cosx+5cosx=4
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document.write( "The answer is: cosx=(4/9), right?\r
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document.write( "But, how do you write this in terms of arccos θ? Would it be: arcoss(4/9)+2πk, for any integer k, or +/-arcoss(4/9)+2π k, for any integer k, or is there just not a solution?
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Algebra.Com's Answer #596442 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the arc value. \n" ); document.write( " \n" ); document.write( "x would terminate in quadrant 1 or quadrant 4, because its cosine is positive. You would need a period of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |