document.write( "Question 974545: Use the given zero to find the remaining zeros of the function:\r
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\n" ); document.write( "\n" ); document.write( "x^3+3x^2+9x-13 \r
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Algebra.Com's Answer #596432 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The other complex zero is -2-3i. Together, these two give the quadratic factor, \"%28x-%28-2%2B3i%29%29%28x-%28-2-3i%29%29\"
\n" ); document.write( "\"%28x%2B2-3i%29%28x%2B2%2B3i%29\"
\n" ); document.write( "\"%28%28x%2B2%29-3i%29%28%28x%2B2%29%2B3i%29\"
\n" ); document.write( "\"%28x%2B2%29%5E2%2B9\"
\n" ); document.write( "\"x%5E2%2B4x%2B4%2B9\"
\n" ); document.write( "\"x%5E2%2B4x%2B13\"\r
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\n" ); document.write( "\n" ); document.write( "Divide the given cubic expression or function by \"x%5E2%2B4x%2B13\". Use polynomial division if necessary. I am not showing that work here, but the quotient will be x-1. The zero for this is +1.
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