document.write( "Question 974532: Two men start from two places 50 km apart.when they travel in opposite directions,they meet in two hours.when they travel in the same direction,one overtakes the other in five hours.Determine their respective rates of traveling \n" ); document.write( "
Algebra.Com's Answer #596418 by lwsshak3(11628)\"\" \"About 
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Two men start from two places 50 km apart.when they travel in opposite directions,they meet in two hours.when they travel in the same direction,one overtakes the other in five hours. Determine their respective rates of traveling
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\n" ); document.write( "let x=rate of faster man
\n" ); document.write( "let y=rate of slower man
\n" ); document.write( "rate=distance/travel time
\n" ); document.write( "..
\n" ); document.write( "x+y=rate travelling in opposite direction (toward each other)
\n" ); document.write( "x-y=rate travelling in same direction
\n" ); document.write( "..
\n" ); document.write( "2(x+y)=50
\n" ); document.write( "5(x-y)=50
\n" ); document.write( "..
\n" ); document.write( "2x+2y=50
\n" ); document.write( "5x-5y=50
\n" ); document.write( "..
\n" ); document.write( "10x+10y=250
\n" ); document.write( "10x-10y=100
\n" ); document.write( "add
\n" ); document.write( "20x=350
\n" ); document.write( "x=17.5
\n" ); document.write( "10y=250-10x=250-175=75
\n" ); document.write( "y=7.5
\n" ); document.write( "rate of faster man=17.5 mph
\n" ); document.write( "rate of slower man=7.5 mph \n" ); document.write( "
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