document.write( "Question 5081: Help--how do i figure this one out? Driving me crazy !!!\r
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document.write( "Twenty bearded men gather. Ten have eight-inch beards, six have ten-inch beards, and four have twelve-inch beards. What is the expected length of a randomly selected man from this group?\r
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document.write( "Tried 10/20 x 6/20 x 4/20 =12inches, that doesn't seem right. Please help! \n" );
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Algebra.Com's Answer #5963 by apeokukuy2k(1)![]() ![]() ![]() You can put this solution on YOUR website! i think that u calculate the probability of selecting a man with eigth -inch beared from the 20 people gathered,then u do likewise for the rest.The one with the highest probability is the most likely to be picked at random.\r \n" ); document.write( "\n" ); document.write( "prob of selecting eight -inch beared from 20 people is 10 combination 1 /20 combination 1.that for 10 inch man is 6 combination 1 / 20 combination 1 and that for a twelve inch beared man is 4 combination 1 / 20 combination 1.the one with the highest probability is the most likely to be selected at random \n" ); document.write( " |