document.write( "Question 974372: Please Verify this w/work : sin^2x-cos^2x/sinx+cosx=sinx-cosx \n" ); document.write( "
Algebra.Com's Answer #596281 by MathLover1(20850)\"\" \"About 
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\"%28sin%5E2%28x%29-cos%5E2%28x%29%29%2F%28sin%28x%29%2Bcos%28x%29%29=sin%28x%29-cos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "....recall the difference of squares rule:\"sin%5E2%28x%29-cos%5E2%28x%29=%28sin%28x%29-cos%28x%29%29%28sin%28x%29%2Bcos%28x%29%29\"; so, we have\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28x%29-cos%28x%29=sin%28x%29-cos%28x%29\"
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