document.write( "Question 974325: 3x-2x^2=7
\n" ); document.write( "(x+3)(x+4)=0 \n" ); document.write( "
Algebra.Com's Answer #596253 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Rewrite first as 2x^2-3x+7=0\r
\n" ); document.write( "\n" ); document.write( "x=(1/4)[3 +/- sqrt(9-56) ;;;; sqrt(-47)\r
\n" ); document.write( "\n" ); document.write( "roots are (3/4) +/- i sqrt (47)\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C15%2C-10%2C250%2C2x%5E2-3x%2B7%2Cx%5E2%2B7x%2B12%29\"\r
\n" ); document.write( "\n" ); document.write( "Not clear if these are supposed to be simultaneous equations.\r
\n" ); document.write( "\n" ); document.write( "x^2+7x+12=0 is the second\r
\n" ); document.write( "\n" ); document.write( "x^2+7x+12=2x^2-3x+7
\n" ); document.write( "-x^2+10x+5=x^2-10x-5
\n" ); document.write( "That solution (common to both equations) is when x=(1/2)[10+/- sqrt(100+20)]=(1/2)[10 +/- 2 sqrt(30]\r
\n" ); document.write( "\n" ); document.write( "Equal at 5 +/-5.47;; -0.47 and 10.47 would be approximate x-solutions.
\n" ); document.write( "Is this what you wanted?\r
\n" ); document.write( "\n" ); document.write( "equal at x=0.55 and 9.45
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