document.write( "Question 974322: Solve for x algebraically: ((e^x)-(e^-x))/2=5. Consider exponential equations of quadratic type.\r
\n" ); document.write( "\n" ); document.write( "I think the answer is supposed to be x=ln(5+sqrt(26)) but I can't figure out the steps to get it. So far I have (1/2)((e^x)-(e^-x))-5=0. From here I'm lost.
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Algebra.Com's Answer #596249 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Solve for x algebraically: ((e^x)-(e^-x))/2=5
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\n" ); document.write( "\"e%5Ex+-+e%5E%28-x%29+=+10\"
\n" ); document.write( "Multiply by e^x
\n" ); document.write( "\"e%5E%282x%29+-+1+=+10e%5Ex\"
\n" ); document.write( "\"e%5E%282x%29+-+10e%5Ex+-+1+=+0\"
\n" ); document.write( "Sub u for e^x
\n" ); document.write( "\"u%5E2+-+10u+-+1+=+0\"
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-10x%2B-1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-10%29%5E2-4%2A1%2A-1=104\".
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\n" ); document.write( " Discriminant d=104 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--10%2B-sqrt%28+104+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-10%29%2Bsqrt%28+104+%29%29%2F2%5C1+=+10.0990195135928\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-10%29-sqrt%28+104+%29%29%2F2%5C1+=+-0.0990195135927845\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-10x%2B-1\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-10x%2B-1+=+%28x-10.0990195135928%29%2A%28x--0.0990195135927845%29\"
\n" ); document.write( " Again, the answer is: 10.0990195135928, -0.0990195135927845.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-10%2Ax%2B-1+%29\"

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\n" ); document.write( "The answer matches.
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