document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974285>Question 974285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right angled triangle has one leg of 12 cm and a hypotenuse of 14 cm. Find the length of the third side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596247 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Assuming one leg is (a) and the hypotenuse is (c),the formula we will use for a right-angled triangle is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+sqrt%28c%5E2+-+a%5E2%29 ALIGN=MIDDLE  ALT=\"b+=+sqrt%28c%5E2+-+a%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where b is the length of the third side.\r<BR>\n" );
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document.write( "We plug the values into the equation,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+b+=+sqrt%2814%5E2+-+12%5E2%29 ALIGN=MIDDLE  ALT=\"+b+=+sqrt%2814%5E2+-+12%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "The length of the third side is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+2sqrt%2813%29 ALIGN=MIDDLE  ALT=\"b+=+2sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  or  b ~ 7.21 cm. \r<BR>\n" );
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document.write( "To show how you obtained the answer <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+2sqrt%2813%29 ALIGN=MIDDLE  ALT=\"b+=+2sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >:\r<BR>\n" );
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document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2814%5E2+-+12%5E2%29+=+sqrt%28196+-+144%29+=+sqrt%2852%29 ALIGN=MIDDLE  ALT=\"sqrt%2814%5E2+-+12%5E2%29+=+sqrt%28196+-+144%29+=+sqrt%2852%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "We separate <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2852%29 ALIGN=MIDDLE  ALT=\"sqrt%2852%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284+%2A+13%29 ALIGN=MIDDLE  ALT=\"sqrt%284+%2A+13%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ---> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%29+%2A+sqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%284%29+%2A+sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > since 4 x 13 = 52. \r<BR>\n" );
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document.write( "We know that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%29+=+2 ALIGN=MIDDLE  ALT=\"sqrt%284%29+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cannot be simplified so we keep it and,\r<BR>\n" );
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document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%2813%29 ALIGN=MIDDLE  ALT=\"2sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or  b ~ 7.21cm.\r<BR>\n" );
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