document.write( "Question 974282: the unit's digit of a number is 3 more then the ten's digit of it. On reversing the order of the digits, the numbers obtained is 2 more then the double of the original number. what is the sum digits of the original number? \n" ); document.write( "
Algebra.Com's Answer #596239 by lwsshak3(11628)\"\" \"About 
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the unit's digit of a number is 3 more then the ten's digit of it. On reversing the order of the digits, the numbers obtained is 2 more then the double of the original number. what is the sum digits of the original number?
\n" ); document.write( "***
\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "..
\n" ); document.write( "u=t+3
\n" ); document.write( "(10u+t)=2(10t+u)+2
\n" ); document.write( "10t+30+t=20t+2u+2
\n" ); document.write( "11t+30=20t+2t+6+2
\n" ); document.write( "11t=22
\n" ); document.write( "t=2
\n" ); document.write( "u=t+3=5
\n" ); document.write( "what is the sum digits of the original number?
\n" ); document.write( "units digit=5
\n" ); document.write( "tens digit=2
\n" ); document.write( "
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