document.write( "Question 974282: the unit's digit of a number is 3 more then the ten's digit of it. On reversing the order of the digits, the numbers obtained is 2 more then the double of the original number. what is the sum digits of the original number? \n" ); document.write( "
Algebra.Com's Answer #596239 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! the unit's digit of a number is 3 more then the ten's digit of it. On reversing the order of the digits, the numbers obtained is 2 more then the double of the original number. what is the sum digits of the original number? \n" ); document.write( "*** \n" ); document.write( "let u=units digit \n" ); document.write( "let t=tens digit \n" ); document.write( ".. \n" ); document.write( "u=t+3 \n" ); document.write( "(10u+t)=2(10t+u)+2 \n" ); document.write( "10t+30+t=20t+2u+2 \n" ); document.write( "11t+30=20t+2t+6+2 \n" ); document.write( "11t=22 \n" ); document.write( "t=2 \n" ); document.write( "u=t+3=5 \n" ); document.write( "what is the sum digits of the original number? \n" ); document.write( "units digit=5 \n" ); document.write( "tens digit=2 \n" ); document.write( " |