document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974265>Question 974265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-y=3,3x-2y=10.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596223 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-y=3<BR>\n" );
document.write( "3x-2y=10<BR>\n" );
document.write( "-2x+2y=-6  Multiply first equation by (-2).  That allows the ys to add to zero.\r<BR>\n" );
document.write( "\n" );
document.write( "x =4; after adding the 2nd equation and the revised first one.<BR>\n" );
document.write( "y=1\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );