document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974230>Question 974230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jet leaves an airport at a speed of 350 km/h for 90 minutes in the direction of N 44* E.  A second jet leaves at the same time but flies due west at a speed of 248 km/h for 90 minutes.  How far are they apart from each other after 90 minutes?  Draw a diagram and solve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596184 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a Law of Cosines Problem<BR>\n" );
document.write( "jet 1 has gone 525 km N44E<BR>\n" );
document.write( "jet 2 has gone 372 km at a bearing of 270, which is 134 degrees apart from jet 1.<BR>\n" );
document.write( "The distance apart is opposite to the angle of 134 degrees\r<BR>\n" );
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document.write( "c^2=a^2+b^2-2abcos C; c^2 is the square of the distance apart they are\r<BR>\n" );
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document.write( "c^2=525^2+372^2-2(575)(372)cos134   The last is -0.695, so the last term is positive\r<BR>\n" );
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document.write( "=843.40 km </SPAN>\n" );
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