document.write( "Question 974152: (Sinx+tanx)(sinx÷1+cosx)=sinx×tanx prove the identity \n" ); document.write( "
Algebra.Com's Answer #596183 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "(Sinx+tanx)(sinx÷1+cosx)=sinx×tanx prove the identity
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document.write( "The left-side will be made equivalent to the right-side
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document.write( " --------- Converting tan x to \"sin+x%2Fcos+x\"
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document.write( " ---- Multiplying by LCD, cos x
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document.write( " ---------- Factoring out GCF, sin x, in numerator
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document.write( " ------- Cancelling 1 + cos x in numerator and denominator
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document.write( "\"%28%28sin+x%29%2F%28cos+x%29%29+%2A+sin+x+=+%28sin+x%29%28tan+x%29\", or \"%28sin+x%29+%2A+%28%28sin+x%29%2F%28cos+x%29%29+=+%28sin+x%29%28tan+x%29\" 
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document.write( "\"%28sin+x%29+%2A+highlight%28tan+x%29+=+%28sin+x%29%28tan+x%29\" -------- Converting \"%28sin+x%29%2F%28cos+x%29\" to tan x
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document.write( "As seen, the left and right sides are congruent, hence the identity has been proven. \n" );
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