document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=974209>Question 974209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the geometric series: 24+ 16+ 32/3+ ... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596172 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ratio is (2/3).  Therefore abs(r)<1\r<BR>\n" );
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document.write( "Sum is a/1-r\r<BR>\n" );
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document.write( "24/(1/3)  =72.\r<BR>\n" );
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document.write( "next terms are 64/9 and 128/27  The first five add to approximately 63.<BR>\n" );
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