document.write( "Question 974205: Hi, \r
\n" ); document.write( "\n" ); document.write( "I have this equation about the volume of a rectangle that i just can;t solve. It says, the width of a rectangular box is 4 times its height, and its length is 10 times more than its height. find the dimensions of the box if its volume is 468 cubic inches.\r
\n" ); document.write( "\n" ); document.write( "I rearranged this in many ways like x= (4x) (10-x) (468) but i didn't know what to do after that. \r
\n" ); document.write( "\n" ); document.write( "thank you \n" ); document.write( "
Algebra.Com's Answer #596171 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x=height
\n" ); document.write( "4x=width
\n" ); document.write( "10x=length\r
\n" ); document.write( "\n" ); document.write( "You would get a 10-x if two summed to 10 and one were x. The other would be (10-x)\r
\n" ); document.write( "\n" ); document.write( "40x^3=468
\n" ); document.write( "x^3=11.7
\n" ); document.write( "x=11.7^(1/3)=2.27\r
\n" ); document.write( "\n" ); document.write( "4x=9.08\r
\n" ); document.write( "\n" ); document.write( "10x=22.7\r
\n" ); document.write( "\n" ); document.write( "22.7*9.08*2.27=467.88, close enough with rounding\r
\n" ); document.write( "\n" ); document.write( "2.2702*9.0808*22.7019=468.00
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