document.write( "Question 974196: Solve the equation
\n" ); document.write( "To clarify on the 1/3^x the denominator has the exponent not the whole fraction, I'm not sure if that matters. Thank you!
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Algebra.Com's Answer #596170 by Alan3354(69443)\"\" \"About 
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\"3%5Ex+%2B+1%2F3%5Ex+=+12\"
\n" ); document.write( "Multiply by 3^x
\n" ); document.write( "\"3%5E%282x%29+%2B+1+=+12%2A3%5Ex\"
\n" ); document.write( "\"3%5E%282x%29+-+12%2A3%5Ex+%2B+1+=+0\"
\n" ); document.write( "Sub u for 3^x
\n" ); document.write( "\"u%5E2+-+12u+%2B+1+=+0\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-12x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-12%29%5E2-4%2A1%2A1=140\".
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\n" ); document.write( " Discriminant d=140 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--12%2B-sqrt%28+140+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-12%29%2Bsqrt%28+140+%29%29%2F2%5C1+=+11.9160797830996\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-12%29-sqrt%28+140+%29%29%2F2%5C1+=+0.0839202169003839\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-12x%2B1\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-12x%2B1+=+%28x-11.9160797830996%29%2A%28x-0.0839202169003839%29\"
\n" ); document.write( " Again, the answer is: 11.9160797830996, 0.0839202169003839.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-12%2Ax%2B1+%29\"

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\n" ); document.write( "3^x = 11.919
\n" ); document.write( "x*log(3) = log(11.919)
\n" ); document.write( "x = log(11.919)/log(3)
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\n" ); document.write( "Do the other 3^x root the same way.
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