document.write( "Question 973934: 1) if x is a rational number and (x+1)^3 -(x-1)^3 / (x+1)^2 - (x-1)^2 = 2, then the sum of numerator and denominator of x is ?\r
\n" ); document.write( "\n" ); document.write( "2) if x^2 + y^2 + 1 = 2x, then x^3 + y^5 = ?
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Algebra.Com's Answer #596147 by KMST(5328)\"\" \"About 
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2) If x^2+y^2+1=2x, then
\n" ); document.write( "x^2+y^2+1-2x=0 ---> (x^2-2x+1)+y^2=0 ---> (x-1)^2+y^2=0 ---> y=0 and x-1=0<-->x=1.
\n" ); document.write( "Then,
\n" ); document.write( "x^3 + y^5 = 1^2 + 0^2 =1 + 0 = 1
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\n" ); document.write( "1) Did you really mean
\n" ); document.write( "(x+1)^3 -(x-1)^3 / (x+1)^2 - (x-1)^2 =\"%28x%2B1%29%5E3+-%28x-1%29%5E3+%2F+%28x%2B1%29%5E2+-+%28x-1%29%5E2\"= 2?
\n" ); document.write( "Or did you mean
\n" ); document.write( "[ (x+1)^3 -(x-1)^3 ] / [ (x+1)^2 - (x-1)^2 ]=\"%28%28x%2B1%29%5E3+-%28x-1%29%5E3%29%2F%28%28x%2B1%29%5E2+-+%28x-1%29%5E2%29\"= 2?
\n" ); document.write( "I like the \"%28%28x%2B1%29%5E3+-%28x-1%29%5E3%29%2F%28%28x%2B1%29%5E2+-+%28x-1%29%5E2%29\" expression,
\n" ); document.write( "because it has a sort of elegant symmetry, and simplifies nicely.
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\n" ); document.write( "You can expand all those cubes and squares and laboriously simplify.
\n" ); document.write( "We can also use special products to simplify the expression with less risk for mistakes.
\n" ); document.write( "If we make the \"system%28a=x%2B1%2Cb=x-1%29\" to save some writing, we can simplify easier.
\n" ); document.write( "We know that \"a%5E3-b%5E3=%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29\" , that \"a%5E2-b%5E2=%28a-b%29%28a%2Bb%29\" , and that \"%28a%2Bb%29%5E2=a%5E2%2B2ab%2Bb%5E2\" .
\n" ); document.write( "So, .
\n" ); document.write( "So, going back to \"x\" ,
\n" ); document.write( "\"%28%28x%2B1%29%5E3+-%28x-1%29%5E3%29%2F%28%28x%2B1%29%5E2+-+%28x-1%29%5E2%29\"=\"%28x%2B1%29%2B%28x-1%29-%28x%2B1%29%28x-1%29%2F%28%28x%2B1%29%2B%28x%2B1%29%29\"=\"2x-%28x%5E2-1%29%2F%282x%29=%284x%5E2-%28x%5E2-1%29%29%2F%222+x%22\"
\n" ); document.write( "=\"%284x%5E2-x%5E2%2B1%29%2F%222+x%22=%283x%5E2%2B1%29%2F%222+x%22\"
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\n" ); document.write( " , so if \"%28%28x%2B1%29%5E3+-%28x-1%29%5E3%29%2F%28%28x%2B1%29%5E2+-+%28x-1%29%5E2%29\"= 2,
\n" ); document.write( "\"%283x%5E2%2B1%29%2F%222+x%22=2\"-->\"3x%5E2%2B1=4x\"-->\"3x%5E2-4x%2B1=0\"-->\"%283x-1%29%28x-1%29=0\"-->\"system%28x=1%2F3%2C%22or%22%2Cx=1=1%2F1%29\" .
\n" ); document.write( "Then, the sum of numerator and denominator of x is either \"1%2B3=4\" or \"1%2B1=2\" .
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\n" ); document.write( "So, if \"%28x%2B1%29%5E3+-%28x-1%29%5E3+%2F+%28x%2B1%29%5E2+-+%28x-1%29%5E2=2\" , then
\n" ); document.write( "\"%28x%5E5%2B4x%5E4%2B9x%5E3%2B15x%5E2%2B2x%2B1%29%2F%28x%5E2%2B2x%2B1%29=2\"-->\"%28x%5E5%2B4x%5E4%2B9x%5E3%2B15x%5E2%2B2x%2B1%29=2%28x%5E2%2B2x%2B1%29\"
\n" ); document.write( "-->\"%28x%5E5%2B4x%5E4%2B9x%5E3%2B15x%5E2%2B2x%2B1%29=2x%5E2%2B4x%2B2\"-->\"%28x%5E5%2B4x%5E4%2B9x%5E3%2B15x%5E2%2B2x%2B1%29-%282x%5E2%2B4x%2B2%29=0\"
\n" ); document.write( "-->\"x%5E5%2B4x%5E4%2B9x%5E3%2B15x%5E2%2B2x%2B1-2x%5E2-4x-2=0\"-->\"x%5E5%2B4x%5E4%2B9x%5E3%2B13x%5E2-2x-1=0\"
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\n" ); document.write( "The rational number \"x=m%2Fn\" ,
\n" ); document.write( "where \"m\" and \"n\" are integers with no common factors,
\n" ); document.write( "that could be a solution to the equation above
\n" ); document.write( "has an \"m\" that is a factor of the independent term, \"-1\" ,
\n" ); document.write( "and an \"n\" which is a factor of the leading coefficient, \"1\" .
\n" ); document.write( "So, \"x=1%2F1=%28-1%29%2F%28-1%29\" or \"x=%28-1%29%2F1=1%2F%28-1%29\" .
\n" ); document.write( "The problem with that, is that
\n" ); document.write( "for \"x=1\" , \"x%5E5%2B4x%5E4%2B9x%5E3%2B13x%5E2-2x-1=1%2B4%2B9%2B13-2-1=24\" ,
\n" ); document.write( "and \"x=-1\" makes the denominator zero.
\n" ); document.write( "For \"x=-1\" , \"%28x%2B1%29%5E2=0\" , and
\n" ); document.write( "\"%28x%2B1%29%5E3+-%28x-1%29%5E3+%2F+%28x%2B1%29%5E2+-+%28x-1%29%5E2\" is undefined.
\n" ); document.write( "My conclusion is that there is no rational value of \"x\" that will make
\n" ); document.write( "\"%28x%2B1%29%5E3+-%28x-1%29%5E3+%2F+%28x%2B1%29%5E2+-+%28x-1%29%5E2\"= 2
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