document.write( "Question 974087: Please help me solve this:\r
\n" ); document.write( "\n" ); document.write( "Find a number t such that the distance between
\n" ); document.write( "(−3, 2)
\n" ); document.write( " and
\n" ); document.write( "(3t, 2t)
\n" ); document.write( " is as small as possible
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Algebra.Com's Answer #596103 by Boreal(15235)\"\" \"About 
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(-3,2) and (3t,2t)\r
\n" ); document.write( "\n" ); document.write( "need to minimize the squared deviations of (2t-2)^2 and (3t+3)^2 \r
\n" ); document.write( "\n" ); document.write( "Take the first derivative and set it equal to zero.\r
\n" ); document.write( "\n" ); document.write( "2(2t-2)*2 + 2(3t+3)*3=0\r
\n" ); document.write( "\n" ); document.write( "8t-16 + 18t +18=0\r
\n" ); document.write( "\n" ); document.write( "26t+2=0
\n" ); document.write( "t=(-1/13)\r
\n" ); document.write( "\n" ); document.write( "(-3,2), (-3/13,-2/13)\r
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\n" ); document.write( "\n" ); document.write( "Distance is sqrt [(36/13)^2) + (28/13)^2 ]=sqrt (7.67+ 4.64)=3.51 units\r
\n" ); document.write( "\n" ); document.write( "Try 0 for t
\n" ); document.write( "(-3,2) and (0,0) ;;; distance sqrt (13)=3.61\r
\n" ); document.write( "\n" ); document.write( "The graph shows the line that the two points are on. The curve is the distance between the two points for various values of t. It is a minimum at (-2/13) for t. The distance from that minimum to the line is minimized.\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-2%2C40%2C13x%5E2%2B4x%2B13%2C%282%2F3%29x%29\"
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