document.write( "Question 974087: Please help me solve this:\r
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document.write( "Find a number t such that the distance between
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document.write( "(−3, 2)
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document.write( " and
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document.write( "(3t, 2t)
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document.write( " is as small as possible \n" );
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Algebra.Com's Answer #596103 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! (-3,2) and (3t,2t)\r \n" ); document.write( "\n" ); document.write( "need to minimize the squared deviations of (2t-2)^2 and (3t+3)^2 \r \n" ); document.write( "\n" ); document.write( "Take the first derivative and set it equal to zero.\r \n" ); document.write( "\n" ); document.write( "2(2t-2)*2 + 2(3t+3)*3=0\r \n" ); document.write( "\n" ); document.write( "8t-16 + 18t +18=0\r \n" ); document.write( "\n" ); document.write( "26t+2=0 \n" ); document.write( "t=(-1/13)\r \n" ); document.write( "\n" ); document.write( "(-3,2), (-3/13,-2/13)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance is sqrt [(36/13)^2) + (28/13)^2 ]=sqrt (7.67+ 4.64)=3.51 units\r \n" ); document.write( "\n" ); document.write( "Try 0 for t \n" ); document.write( "(-3,2) and (0,0) ;;; distance sqrt (13)=3.61\r \n" ); document.write( "\n" ); document.write( "The graph shows the line that the two points are on. The curve is the distance between the two points for various values of t. It is a minimum at (-2/13) for t. The distance from that minimum to the line is minimized.\r \n" ); document.write( "\n" ); document.write( " |